36x^2-63x^2=27x

Solution for 36x^2-63x^2=27x equation:

36x^2-63x^2=27x

We move all terms to the left:

36x^2-63x^2-(27x)=0

We add all the numbers together, and all the variables

-27x^2-27x=0

a = -27; b = -27; c = 0;
Δ = b2-4ac
Δ = -272-4·(-27)·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-27}{2*-27}=\frac{0}{-54}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+27}{2*-27}=\frac{54}{-54}
=-1
$